A uniform ring of mass m and radius R is in uniform pure rolling motion on a horizontal surface. The velocity of the centre of ring is `V_(0)`. The kinetic energy of the segment ABC is: A. `(mV_(0)^(2))/(2)-(mV_(0)^(2))/(pi)`B. `(mv_(0)^(2))/(2)+(mv_(0)^(2))/(pi)`C. `(mv_(0)^(2))/(2)`D. `mv_(0)^(2)`

A uniform ring of mass m and radius R is in uniform pure rolling motio

1.	A uniform ring of mass m and radius R is in uniform pure rolling motion on a horizontal surface. The velocity of the centre of ring is `V_(0)`. The kinetic energy of the segment ABC is: A. `(mV_(0)^(2))/(2)-(mV_(0)^(2))/(pi)`B. `(mv_(0)^(2))/(2)+(mv_(0)^(2))/(pi)`C. `(mv_(0)^(2))/(2)`D. `mv_(0)^(2)`
Answer» Correct Answer - A

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