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A uniform rod AB of mass .m. length .2a. is allowed to fall under gravity with AB in horizontal. When the speed of the rod is .v., suddenly the end .A. is fixed. Find the angular velocity with which it begins to rotat. |
Answer» <html><body><p></p>Solution :`L_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)=L_(2)`<br/>`mva = I omega`<br/>`mva = (m(<a href="https://interviewquestions.tuteehub.com/tag/2a-300249" style="font-weight:bold;" target="_blank" title="Click to know more about 2A">2A</a>)^(2))/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)omega rArr omega = (<a href="https://interviewquestions.tuteehub.com/tag/3v-310794" style="font-weight:bold;" target="_blank" title="Click to know more about 3V">3V</a>)/(4a)`<br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_B_C07_SLV_089_S01.png" width="80%"/></body></html> | |