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A uniform rod of length 1 and mass m is suspended by two vertical inextensible string as shown in the fig. The tension in the left string when right string snaps, is |
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Answer» Solution :`mg-T=ma ""…(1)` `alpha=(tau)/(I)=(mg(L)/(2))/((ml^(2))/(3))=(3g)/(2I) ""…(2)` `a=(l)/(2) alpha ….(3)` solving EQUATION (1), (2) and (3) we GET `T=(mg)/(4)`
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