1.

A uniform rod of length 200 cm and mass 500 g is balanced on a wedge placed at 40 cm mark. A mass of 2 Kg is suspended from the rod at 20 cm and another unknown mass ′m′ is suspended from the rod at 160 cm mark as shown in the figure. Find the value of m such that the rod is in equilibrium.(g=10 ms−2)

Answer»

A uniform rod of length 200 cm and mass 500 g is balanced on a wedge placed at 40 cm mark. A mass of 2 Kg is suspended from the rod at 20 cm and another unknown mass m is suspended from the rod at 160 cm mark as shown in the figure. Find the value of m such that the rod is in equilibrium.

(g=10 ms2)






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