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A uniform rod of length `4m` and mass `2sqrt(2)kg` revolves with constant angular velocity `omega` what a vertical axis through a smooth joint `A` at one extermly of the rod so that it describes a cone of semi vertical angle `53^(@)` as shown in the figure. Choose the correct statement (s). `(g=10m//s^(2))` A. The value of angular velocity `omega` is `2.5rad//s`B. The angle between hinge reaction at point `A` and vertical axis `AC` is `45^(@)`C. The magnitude of hinge reaction at point `A` is `40N`D. The angular momentum of the rod is constant.

Answer» `F=2xx(mu_(0)I_(1))/(2piR)xxI_(2)l=(2xx2xx10^(-7)xx50xx20xx0.50)/(0.25)=8xx10^(-4)N`


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