1.

A uniform rod of length 60 cm and mass 6kg is acted upon by two forces as shown in the diagram. The force exerted by 45cm part of the rod on 15cm part of the rod is​

Answer»

EXPLANATION:Mass of 10cm= M(L-x)/L=M*10/30=M/3

Similarly, mass of 20CM= M*20/30=2M/3

Draw the FBD for both the MASSES with their reaction force on each block.

From mass M/3 we GET:

R-20=Ma/3....1)

R=Ma/3 + 20

From mass 2M/3:

32-R= 2M/3

Substitute the value of R here.. we get Ma=12

Substitute this value of "Ma" in EQUATION 1)

Hence we get the value of reaction force R as 24N


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