1.

A uniform rod of length Lhasa mass per unit length lambda and area of cross-section A. The elongation in the rod is l due to its own weight. If it is suspended fromthe ceiling of a room, the Young's modulus of the rod is

Answer»

`( 2 LAMBDA G L^(2) )/( Al)`
` ( lambda g L^(2) )/( 2 Al)`
`( 2 lambda g L^(2) )/( Al)`
`( lambda gl^(2))/( AL)`

Answer :B


Discussion

No Comment Found