1.

A uniform rod of mass M_(1)is hinged at its upper end. A particle of mass M_(2)moving horizontally strikes the rod at its mid point elastically. If the particle comes to rest after collision, the value of (M_(1))/(M_(2)) is -

Answer»

`(3)/(4)`
`(4)/(3)`
`(2)/(3)`
`(3)/(2)`

SOLUTION :`L_(H)=M_(2)V(L)/(2)=(M_(1)L^(2))/(3)omega`
`omega=(2M_(2)v)/(2M_(1)L)""…(1)`
for `e=1, v_(CM)=v -(omegaL)/(2)""…(2)`
`RARR (2V)/(L)=(3M_(2)v)/(2M_(1)L)`
`rArr (M_(1))/(M_(2))=(3)/(4)`


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