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A uniform rod of mass M_(1)is hinged at its upper end. A particle of mass M_(2)moving horizontally strikes the rod at its mid point elastically. If the particle comes to rest after collision, the value of (M_(1))/(M_(2)) is - |
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Answer» `(3)/(4)` `omega=(2M_(2)v)/(2M_(1)L)""…(1)` for `e=1, v_(CM)=v -(omegaL)/(2)""…(2)` `RARR (2V)/(L)=(3M_(2)v)/(2M_(1)L)` `rArr (M_(1))/(M_(2))=(3)/(4)` |
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