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A uniform rod of mass m and lengh I makes a constant angle theta with an axis of rotation which passes through one end of therod. Find the moment of inertia about this axis. |
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Answer» SOLUTION :MOMENT of inertia of the rod about the axis which is passing through itscentre of gravity is `I_(a)=(Ml^(2))/(12)=Ml^(2) sin^(2) THETA//12` Moment of inertia of a uniform rod of mass mand length / about one axis which PASSES through one end of the rod `I_(0)=(Ml^(2) sin^(2) theta)/(4)=(Ml^(2)sin^(2) theta)/(12)+(Ml^(2) sin^(2) theta)/(4)=(1)/(3)Ml^(2) sin^(2) theta`
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