1.

A uniform rod of mass m and lengh I makes a constant angle theta with an axis of rotation which passes through one end of therod. Find the moment of inertia about this axis.

Answer»

SOLUTION :MOMENT of inertia of the rod about the axis which is passing through itscentre of gravity is
`I_(a)=(Ml^(2))/(12)=Ml^(2) sin^(2) THETA//12`
Moment of inertia of a uniform rod of mass mand length / about one axis which PASSES through one end of the rod
`I_(0)=(Ml^(2) sin^(2) theta)/(4)=(Ml^(2)sin^(2) theta)/(12)+(Ml^(2) sin^(2) theta)/(4)=(1)/(3)Ml^(2) sin^(2) theta`


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