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A uniform rod of mass m and length is acted upon by the forces F_(1) and F_(2) Find that: a. linear-and angular acceleration of the rod. b. value of x for which the point P does not accelerate. |
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Answer» Solution :a. Equation of motion `F_(1)+F_(2)=ma` or `2F-F=maimpliesa=(3F)/m`…….i TORQUE equation about centre of mass. `2F.l/2-F.x=((ML^(2))/12)alpha` `implies alpha(12F(l-x))/(ml^(2))` ………ii b. If point `P` does not ACCELERATION `veca_(P)=veca_(P,C)+veca_(C)` As `a_(P)=0=-ax+aimpliesax=a` `(12F(l-x))/(ml^(2))=(3F)/m` which given `x=l/2` |
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