1.

A uniform rod of mass m and length is acted upon by the forces F_(1) and F_(2) Find that: a. linear-and angular acceleration of the rod. b. value of x for which the point P does not accelerate.

Answer»

Solution :a. Equation of motion
`F_(1)+F_(2)=ma`
or `2F-F=maimpliesa=(3F)/m`…….i
TORQUE equation about centre of mass.
`2F.l/2-F.x=((ML^(2))/12)alpha`
`implies alpha(12F(l-x))/(ml^(2))` ………ii
b. If point `P` does not ACCELERATION
`veca_(P)=veca_(P,C)+veca_(C)`
As `a_(P)=0=-ax+aimpliesax=a`
`(12F(l-x))/(ml^(2))=(3F)/m`
which given `x=l/2`


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