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A uniform rod of mass m and length l is at rest on smooth horizontal surface. An impulse P is applied to end B as shown. Distance travelled by the centre of the rod, while rod rotates by `90^(@)`A. `(pi l)/(7)`B. `(pi l)/(4)`C. `(pi l)/(12)`D. `(pi l)/(5)` |
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Answer» Correct Answer - C angle rotated `= (pi)/(2)` and we know that `theta = omega t` `rArr t = (theta)/(omega) rArr t = ((pi)/(2))/((6P)/(mL)) rArr t = (pi mL)/(12P)` Distance covered by centre of rod. `s = v xx t rArr s = (P)/(m) xx (pimL)/(12P) rArr s = (pi L)/(12)` |
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