1.

A uniform rod of mass m and length l is suspended by means of two light inextensible strings at the rnds of rod. Tension in one stringimmediately after the other string is cut is

Answer»

Solution :`mg-T=ma ""`…..(1)
`alpha = (tau)/(I)=(mg(l)/(2))/((ml^(2))/(3))=(3G)/(21) ""`…..(2)
`a=(l)/(2)alpha ""`….(3)
Solving equations (1), (2) and (3)
we GET, `T=(mg)/(4)`


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