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A uniform rod of mass m and length l is suspended by means of two light inextensible strings at the rnds of rod. Tension in one stringimmediately after the other string is cut is |
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Answer» Solution :`mg-T=ma ""`…..(1) `alpha = (tau)/(I)=(mg(l)/(2))/((ml^(2))/(3))=(3G)/(21) ""`…..(2) `a=(l)/(2)alpha ""`….(3) Solving equations (1), (2) and (3) we GET, `T=(mg)/(4)`
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