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A uniform rod of mass m and length l is suspended by means of two light inextensible strings at the ends of rod. Tension in one string immediately after the other string is cut is |
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Answer» SOLUTION :`MG-T=ma`……….`(1)` `alpha=(TAU)/(I)=(mg.(l)/(2))/((ml^(2))/(3))=(3g)/(2I)`………..`(2)` `a=(l)/(2)alpha`………`(3)` Solving equations `(1)`, `(2)` and `(3)` we get, `T=(mg)/(4)`
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