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A uniform rod of mass m and length / makes a constant angle theta with an axis of rotation which passes through one end of the rod. Its moment of inertia about this axis is |
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Answer» `(ML^(2))/(3)` Moment of INERTIA of the element about the AXIS = `((m)/(l) ""dx) (x sin theta)^(2)` `I = (m)/(l) sin^(2) theta int_(0)^(1) x^(2) dx = (ml^(2))/(3) sin^(2) theta`
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