1.

A uniform rod of mass m and length / makes a constant angle theta with an axis of rotation which passes through one end of the rod. Its moment of inertia about this axis is

Answer»

`(ML^(2))/(3)`
`(ml^(2))/(3) sin theta`
`(ml^(2))/(3) sin^(2) theta`
`(ml^2)/(3) cos^(2) theta`

Solution :Mass of an arbitrary element dx = `((m)/(l))` dx
Moment of INERTIA of the element about the AXIS = `((m)/(l) ""dx) (x sin theta)^(2)`
`I = (m)/(l) sin^(2) theta int_(0)^(1) x^(2) dx = (ml^(2))/(3) sin^(2) theta`


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