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A uniform solid disk of mass `m = 3.0 kg` and radius `r = 0.20 m` rotates about a fixed axis perpendicular to its face with angular frequecy `0.6 rad/s`. The magnitide of the angular momentum of the disk when the axis of rotation momentum of the disk when the axis of rotation passes through a point midway between the centre and the rim is.A. `0.72 kg.m^2//s`B. `0.54 kg.m^2//s`C. `0.36 kg.m^2//s`D. `1.08 kg.m^2//s` |
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Answer» Correct Answer - B (b) For a point midway between the centre and the rim, we use the parallel-axis theorem to find the moment of inertia about this point. Then, `L = I omega = [(1)/(2) MR^2 + M((R)/(2))^2] omega` =`(3)/(4) (3.00 kg)(0.200 m)^2 (6.00 rad//s)` =`0.540 kg . m^2//s`. |
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