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A uniform spherical shell rolls down a fixed inclined pla ne without sliping. Find the ratio of | rotational kinetic energy to translational kinetic energy as it reaches lowest point of the incline. |
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Answer» Solution :As there is no slip, `v=Romega` is valid and rotational KINETIC energy `K_(R)=(1)/(2)I_(CM)omega^(2)=(1)/(2)mk^(2)omega^(2)` and translational kinetic energy `K_(T)=(1)/(2)MV^(2)=(1)/(2)mR^(2)omega^(2)` therefore `(K_(R))/(K_(T))=(K^(2))/(R^(2))=(2)/(3)` |
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