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A uniform table of mas M stays horizontally and symmetrically on two wheels rotatig in opposite directions figure. The separsation between the wheels is L. The friction coefficeint between each whee, and the plate is mu. Find the time period of oscilationof the pate if it is slightly displaced along its length and released. |
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Answer» `R_1+R_2=mg` Taking moment about g we get `R_1(l/2-x)=R_2(1/2-x)` `=(mg-R_1)(l/2+x)…………1 `ltbr.gt `S, R_1(l/2-x)=(mg-R_1)(l/2+x)` `rarr R_1 1/2-R_1x=` `mgl/2-R_1x+mgx-R_1l/2` L `rarrR-1l/2+R_1l/2=mg(x+1/2)` `rarr R_1(l/2+l/2)=mg((2x+1)/2)` `rarr R_1l=mg(2x+1) R_1=mg((1+2x)/(2l)` .........i Now, `F_1=muR_1=mumg((1+2x))/(2l)` similarly `F_2=muR=mumg((1+2x))/(2l)` similarlty `F_2=muR_2=muMg((1+2x))/(2l)` SIN `F_1gtF_2` `rarrF_1-F_2=ma-(2mu(mg)/l)x` `a/x=2mu=(mg)/l=omega^2` `rarr =omegamusqrt(g/l)` `: Time period `=2pisqrt(l/(2mug))` |
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