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A uniform tube of length 60 cm stands vertically with its lower end dipping into water . First two air column lengths above water are 15 cm, when the tube resonds to a vibrating fork of frequency 500 H_(Z) . Find the lowest frequency to the tube will respond when it is open at both ends. |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`(lambda)/(2) = (45 - 15) cm` <br/> `:. lambda = <a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a> cm` <br/> `nu = f lambda = (500) (0.6)` <br/> `= <a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a> m//s` <br/> Lowest frequency when <a href="https://interviewquestions.tuteehub.com/tag/open-586655" style="font-weight:bold;" target="_blank" title="Click to know more about OPEN">OPEN</a> from both ends is `(nu)/(<a href="https://interviewquestions.tuteehub.com/tag/2l-300409" style="font-weight:bold;" target="_blank" title="Click to know more about 2L">2L</a>)` . <br/> `= (300)/(2 xx0.6) = 250 H_(Z)`</body></html> | |