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InterviewSolution
| 1. |
A uniform wire of length L, diameter D ad densityP is stretched under a tension T. The correct relation between its fundamental freqency 'f', the length L and the diameter D is : |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> prop (<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)/(D^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))` <br/>`f prop (1)/(D^(2))` <br/>`f prop (1)/(LD)`<br/>`f prop (1)/(L sqrt(D))` </p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>= `(1)/(2l ) sqrt((T)/(m))` <br/> Now mass per unit length m `rho . A= rho. (pi D^(2))/(4 ) ` <br/> v `= (1)/(2l) sqrt((T)/((pi D^(2))/(4))) = (1)/(l) sqrt((T)/(pi D^(2))) ` <br/> For <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> tension T, v `prop (1)/(l)` <br/> So correct choice is c.</body></html> | |