A uniform wire of mass m, length L, area of cross-section A and Young's modulus Y hange from the ceiling. Its elongation under its own weight will be

A uniform wire of mass m, length L, area of cross-section A and Young'

1.	A uniform wire of mass m, length L, area of cross-section A and Young's modulus Y hange from the ceiling. Its elongation under its own weight will be
Answer» ZERO `(mgL)/(2AY)` `(mgL)/(AY)` `(2mgL)/(AY)` Solution :In CASE of elongation by its own WEIGHT MG will act at centre of gravity of the wire so that length of wire which is stretched will be `((L)/(2))`. `:. Delta L= ((mg) ((L)/(2)))/(AY) = (mgL)/(2AY)`