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A uniform wire of resistance `9 Omega` is cut into 3 equal parts. They are connected in form of equilateral triangle `ABC`. A cell of e.m.f. `2V` and negligible internal resistance is connected across `B` and `C`. Potential difference across `AB` isA. 0.4 V`B. 0.4 V`C. `1.2 V`D. `2.4V` |
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Answer» Correct Answer - a The minimum potential difference across as zero of network `= Ir//6 = 2.4 xx 1//6 = 0.4 V` |
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