1.

A vanadium ...............

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Solution :SINCE magnetic moment `=1.73` B.M. `=sqrt(3)`
`IMPLIES` no. of unpaired electron in vanadium will be 1, so it confirms that V will exist as `V^(4+)` in its compound.
According to Faraday's first LAW
`W=(Axxixxt)/(nxx96500)`
`102xx10^(-3)=(51xxixx8)/(4xx96500)`
`i=96.5` amp


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