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A vanadium ............... |
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Answer» `IMPLIES` no. of unpaired electron in vanadium will be 1, so it confirms that V will exist as `V^(4+)` in its compound. According to Faraday's first LAW `W=(Axxixxt)/(nxx96500)` `102xx10^(-3)=(51xxixx8)/(4xx96500)` `i=96.5` amp |
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