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A variable capacitor is connected to a 200V battary. If its capacitance is changed from 2μF to XμF, the decrease in energy of the capacitor is 2 x 10-2J. The value of X is -(a) 1μF(b) 2μF(c) 3μF(d) 4μF |
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Answer» Option : (d) 4μF |
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