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A variable frequency AC source is connected to a capacitor. How will the displacement current change with decrease in frequency? |
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Answer» Current through capacitor, `I_(~)=E_(~)/(X_C)=(E_(~))/(1//omegaC)=omegaCE_(~) or I_(~)propv`. therefore, decrease in frequency v of a.c. source decrease the conduction current. As displacement current =conduction current, hence decrease in v decrease displacement current in circuit. |
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