1.

A vector alongthe bisector of angle between the vectors vecb and vecc is,

Answer»

`(2+sqrt(3))HATI + (1-sqrt(3))hatj+(2+sqrt(3))hatk`
`(2+sqrt(3))hati+(1-sqrt(3))hatj-(2+sqrt(3))hatk`
`(2+sqrt(3))hati-(1-sqrt(3))hatj-(2+sqrt(3))hatk`
`(2+sqrt(3))hati-(1-sqrt(3))hatj+(2+sqrt(3))hatk`

SOLUTION :Vector along the bisectors is
`(hati-hatj+hatk)/sqrt(3) + (4hati+2hatj+4hatk)/6`
`1/3(2+sqrt(3))hati+(1-sqrt(3))hatj+(2+sqrt(3))hatk`
`THEREFORE` VECTORS is `(2+sqrt(3))hati+(1-sqrt(3))hatj+(2+sqrt(3))hatk`


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