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A vector alongthe bisector of angle between the vectors vecb and vecc is, |
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Answer» `(2+sqrt(3))HATI + (1-sqrt(3))hatj+(2+sqrt(3))hatk` `(hati-hatj+hatk)/sqrt(3) + (4hati+2hatj+4hatk)/6` `1/3(2+sqrt(3))hati+(1-sqrt(3))hatj+(2+sqrt(3))hatk` `THEREFORE` VECTORS is `(2+sqrt(3))hati+(1-sqrt(3))hatj+(2+sqrt(3))hatk` |
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