A vector sqrt(3)hati + hatjrotates about its tail through an angle 30^(@)in clock wise direction then the new vector is

A vector sqrt(3)hati + hatjrotates about its tail through an angle 30^

1.	A vector sqrt(3)hati + hatjrotates about its tail through an angle 30^(@)in clock wise direction then the new vector is
Answer» Solution :The magnitude of `sqrt(3) HAT(i) + hat(j)` is `sqrt(3+1) = 2` The angle made by the vector with x-axis is `Tan THETA = (A_(y))/(A_(x)) = (1)/(sqrt(3))` `therefore theta = 30^(@)` When the GIVEN vector rotates `30^(@)` in CLOCK wise is directions changes along x-axis but its magnitude does not change. `therefore` The new vector is `2hat(i)`