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A vehicle of 100 kg is moving with velocity of 5 m/s. How much force will be required to stop in 1/10 sec ? |
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Answer» Solution :`m= 100 KG` `v_(0) = 5m//s` `t = (1)/(10) SEC` `=100 (-50) ` `=- 5000 N` `a= (V-v_(0))/( t )= (6-5)/((1)/(10))` `=-50` Negtive SIGN indicateretardingforce |
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