A vehicle of mass 10kg is moving with a velocity of 5 ms^(-1) .To stop it in 1//10 sec the required force in opposite direction is

A vehicle of mass 10kg is moving with a velocity of 5 ms^(-1) .To stop

1.	A vehicle of mass 10kg is moving with a velocity of 5 ms^(-1) .To stop it in 1//10 sec the required force in opposite direction is
Answer» 5000N 500N 50N 1000N Solution :`F=(DP)/(DT), F=(m(v-u))/(t)`