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A vehicle of mass 1250 kg is driven with an acceleration 0.25 ms^(-2) along a straight level road against an external resistive force 500 N. Calculate the power delivered by the vehicle's engine if the velocity of the vehicle is 30 ms^(-1). |
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Answer» Solution :The VEHICLE.s engine has to do work against RESISTIVE force and make vehicle to move with an acceleration. THEREFORE, POWER delivered by the vehicle engine is `p=("resitive force"+"mass"xx"acceleration") ("velocity")` ` p=vecF_("tot").vecv=F_("resistive"+F)vecv` `p=vecF_("tot").vecv=(F_("resistive")+ma)vecv` `=(500N+(1250kg)xx(0.2 ms_(-2))(30MS^(-1))=22.5kW` |
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