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A vehicle of mass `m` is moving on a rough horizontal road with momentum `P` . If the coefficient of friction between the tyres and the road br mu, then the stopping distance is:A. `(P)/(2mumg)`B. `(P^(2))/(2mumg)`C. `(P)/(2mum^(2)g)`D. `(P^(2))/(2mum^(2)g)` |
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Answer» Correct Answer - D `S=(u^(2))/(2mug)=(m^(2)-u^(2))/(2mumg^(2))=(P^(2))/(2mumg^(2)g)` |
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