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A vehicle of mass `M` is moving on a rough horizontal road with a momentum P If the coefficient of friction between the tyres and the road is `mu` is then the stopping distance is .A. `(P)/(2muMg)`B. `(P^(2))/(2muMg)`C. `(P^(2))/(2muM^(2)g)`D. `(P^(2))/(2muM^(2)g)` |
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Answer» Correct Answer - C `P =mv, v^(2) -u^(2) =2as, a =mu_(k)g` . |
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