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A vertical glass capillary tube open at both ends contain some water (T.P). Then the length of water column L = _____ |
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Answer» Solution :`P_(2)=P_(1)(-2T)/R=P_(0)(-2T)/R` `P_(3)=P_(2)+LPg` `P_(4)=P_(3)-(2T)/RrArrLpg=(4T)/RrArrL=(4T)/(RPG)` here `r=Rcostheta=R` 
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