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A vertical pole of length `l`, density `rho`, area of cross section `A`, floats in two immiscible liquids of densities `rho_(1)` and `rho_(2)`. In equilibrium position the bottom end is at the interface of the liquids. When the cylinder is displaced vertically, the time period of oscillation is.......... A. `pisqrt((rhol)/((rho_(1)+rho_(2))g))`B. `pi sqrt((rhol)/(g)) ((1)/(sqrt(rho_(1)))+(1)/(sqrt(rho_(2))))`C. `pi sqrt(((rho_(1)+rho_(2))l)/(rhog))`D. `pi sqrt((l)/(rhog)) (sqrt(rho_(1))+sqrt(rho_(2)))` |
Answer» Correct Answer - B Here interface acts as mean position of `SHM`: `:.` time period, `T = (T_(1))/(2) +(T_(2))/(2)` `T_(1) = 2pi sqrt((rhol)/(rho_(2)g)): T_(2) = 2pi sqrt((rhol)/(rho_(1)g))` |
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