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A vertical stick of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower. |
Answer» Let AB be a tower CD be a stick , CD = 6m Shadow of AB is BE = 28cm Shadow of CD is DF = 4m At same time light rays from sun will fail on tower and stick at the same angle So,∠DCF = ∠BAE And ∠DFC = ∠BEA ∠CDF = ∠ABE (Tower and stick are vertically to ground) Therefore ΔABE ~ ΔCDF (By AAA similarity) So, AB/CD = BE/DF AB/6 = 28/4 AB/6 = 7 AB = 7 x 6 AB = 42 m So, height of tower will be 42 meter. |
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