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A very long magnet of pole strength `4 Am` is placed vertically with its one pole on the table. The distance form the pole, the neutral point will be formed is `(B_(H)=4xx10^(-5)T)`A. `0.5m`B. `0.1m`C. `0.15m`D. `6.66m` |
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Answer» Correct Answer - B `B_(H)=(mu_(0))/(4pi)(m)/(d^(3))` |
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