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A vessel at 1000 K contains carbon dioxide with a pressure of 0.5 atm. Some of the carbon dioxide is converted to carbon monoxide on addition of graphite. Calculate the value of K it the total pressure at equilibrium is `0*8` atm. |
Answer» `CO_(2) (g) + C (s) hArr 2 CO (g)` Suppose decrease in pressure of `CO_(2)` after reaction = p atm Then increase in pressure due to CO= 2 p Pressure of `CO_(2)` at equilibrium `=(0.5 - p)` atm `:." Final total pressure " (0.5- p) + 2p = 0*5 + p = 0.8 " atm"` (Given) `:. p= 0*3 " atm. Hence we have "` `p_(CO_2) = 0*5 - 0*3 = 0*2 " atm "` `and " "p_(CO) = 2 xx 0*3 = 0*6 " atm" ` `:. K = (P_(cO)^(2))/P_(CO_(2)) = (0.6)^(2)/(0*2) = 1*8` |
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