A. vessel contains 5 litres of Liquid A and 20 litres of Liquid B. 20% of the contents of the vessel are removed. To the remaining contents, x litres of Liquid A is added to reverse the ratio of Liquid A and Liquid B. Then y litres of Liquid B is added again to reverse the ratio of Liquid A and Liquid B. Quantity I: Value of 'y' Quantity II: Value of 'x'(a) QuantityI= Quantity II or No relation(b) QuantityI≤ Quantity II(c) QuantityI≥ Quantity II(d) QuantityI> Quantity II

A. vessel contains 5 litres of Liquid A and 20 litres of Liquid B. 20

1.	A. vessel contains 5 litres of Liquid A and 20 litres of Liquid B. 20% of the contents of the vessel are removed. To the remaining contents, x litres of Liquid A is added to reverse the ratio of Liquid A and Liquid B. Then y litres of Liquid B is added again to reverse the ratio of Liquid A and Liquid B. Quantity I: Value of 'y' Quantity II: Value of 'x'(a) QuantityI= Quantity II or No relation(b) QuantityI≤ Quantity II(c) QuantityI≥ Quantity II(d) QuantityI> Quantity II
Answer» Quantity `I=` Quantity II or No relation Quantity `I le` Quantity II Quantity `I ge` Quantity II Quantity `Igt` Quantity II Solution :After `20%` of the contents of the vessel are romoved, Remaining contents `=(80)/(100)(25)=20` litres. Ratio of Liquid A and Liquid B in it `=1:4.` `therefore` It contains `4/5(10)=8` litres of Liquid B and 2 litres of Liquid A. To reverse the ratio, 2 litres of Liquid A must be MADE 32 litres. `thereforex=30` litres of Liquid A must be added. To reverse this ratio again 8 litres of Liquid B must be made `4(32)=128` litres. `therefore y=128-8=120` litres of Liquid B must be added. Quantity I: 'y' = 120 litres Quantity II: 'x' = 30 litres Quantity `I gt` Quantity II