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A vessel contains equal weights of He and CH_(4)gases at 20 bar pressure. Due to the leakage, the gases in the vessel started effusing out. What is the volume ratio of He and CH_(4)gases coming out initally

Answer»

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SOLUTION :`n_(He) = x/4 = n_1 , n_(CH_4) = x/16 = n_2 , (n_1)/(n_2) = 4/1`.
`(gamma_(He))/(gamma_(CH_4)) = (P_(He))/(P_(CH_4)) SQRT(16/4) = 4/1 sqrt(16/4) = 8:1`.


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