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A vessel contains He and H_(2) in the molar ratio 1 : 5. The ratio of mean transitional kinetic energies, at the same tempreatures is |
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Answer» Solution :(d) `KE=(3)/(2)PV=(3)/(2)nRT` `((KE)He)/((KE)H_(2))=((3)/(2)RT)/((3)/(2)RT)((1)/(5))=1 : 5` |
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