1.

A vessel contains He and H_(2) in the molar ratio 1 : 5. The ratio of mean transitional kinetic energies, at the same tempreatures is

Answer»

`1 : 1`
`1 : 2`
`2 : 1`
`1 : 5`

Solution :(d) `KE=(3)/(2)PV=(3)/(2)nRT`
`((KE)He)/((KE)H_(2))=((3)/(2)RT)/((3)/(2)RT)((1)/(5))=1 : 5`


Discussion

No Comment Found