A vessel contains one mole of O_2 gas (molar mass 32) at a temperature T. The pressure of the gas 1s.What will be the pressure of one mole of He (molar mass 4) at a temperature 2t in an identical vessel?

A vessel contains one mole of O_2 gas (molar mass 32) at a temperature

1.	A vessel contains one mole of O_2 gas (molar mass 32) at a temperature T. The pressure of the gas 1s.What will be the pressure of one mole of He (molar mass 4) at a temperature 2t in an identical vessel?
Answer» <P> Solution :Pressure of oxygen at temperature T is Let the pressure of Helium be `P_("He")`at a temperature 2 T Number of molecules of Helium `n_("OXY")=32/16=2` Number of molecules of Oxygen `n_(He) = 4/2=2` It is GIVEN that `(V_("OXY"))/(V_("He)) = 1` From standard GAS equation `P=(nRT)/V` We get , `P_("He")/(P_("OXY"))=(n_(He))/(n_("OXY"))xxT_(He)/(T_("OXY"))xxV_("OXY")/(V_(He))` `P_("He")/(P_("OXY"))=2/2xx(2T)/Txx1` `:. (P_(He))/(P_("OXY"))=2` `:.`Pressure of 1 mole of Helium =2 `xx` Pressure of 1 mole of oxygen