A vessel has equal mass of co2 and n2o. the mole fraction of co2 is...

1.	A vessel has equal mass of co2 and n2o. the mole fraction of co2 is...
Answer» Answer: Initial partial pressures of CO and CO 2 are 3 atm and 2 atm respectively. 2CO(g)⇋CO 2 (g)+C(s) To reach equilibrium, 2x atm of CO REACTS to form x atm of CO 2 The equilibrium partial pressures of CO and CO 2 are 3−2x atm and 2+x atm respectively. Total equilibrium pressure is (3−2x)+(2+x)=5−x atm. But it is EQUAL to 4.5 atm. 4.5=5−x x=5−4.5 x=0.5 p CO :p CO 2 =(3−2x):(2+x)=(3−2(0.5)):(2+1(0.5))=2:2.5=4:5 K p = P CO2 P CO 2 K p = 22 2.5 K p =0.625atm −1 The DISSOCIATION of CO = 32x = 32(0.5) =0.333 The % dissociation of CO =100×0.333=33.3

Answer»

Answer:

Initial partial pressures of CO and CO 2 are 3 atm and 2 atm respectively.

2CO(g)⇋CO 2 (g)+C(s)

To reach equilibrium, 2x atm of CO REACTS to form x atm of CO 2

The equilibrium partial pressures of CO and CO 2

are 3−2x atm and 2+x atm respectively.

Total equilibrium pressure is (3−2x)+(2+x)=5−x atm. But it is EQUAL to 4.5 atm.

4.5=5−x

x=5−4.5

x=0.5

p CO

:p CO 2

=(3−2x):(2+x)=(3−2(0.5)):(2+1(0.5))=2:2.5=4:5

K p

= P CO2

P CO 2

K p

= 22

2.5

K p

=0.625atm −1

The DISSOCIATION of CO = 32x

= 32(0.5)

=0.333

The % dissociation of CO =100×0.333=33.3

Discussion