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InterviewSolution
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A vessel of volume `8.0xx10^(-3) m^(3)` contains an ideal gas at 300K and 200kPa. Calulate the amount of the gas (in moles) leaked assuming that the tenperature remains constant. |
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Answer» As the gas leaks out, the volume and the temperature of the remaining gas do not change. The number of moles in the vessel is given by `n=(pV)/(RT)`. The number of moles in the vessel before the leakage is `n_(2)=(p_(1)V)/(RT)` and that after the leakage is `n_(2)=(p_(2)V)/(RT)`.`Thus, the amount leaked is `n_(1)-n_(2)=((p_(1)-p_(2))V)/(RT)` ltbgt `=((200-125)xx10^(3) N m^(-2)xx8.0xx10^(-3)m^(3))/((8.3JK^(-1)mol^(-1))xx(300K))` `=0.24mol^(-1).` |
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