A vesselat 1000 K containsCO_(2) with a pressure of 0.5 atm . Some of the CO_(2) is converted intoCO on the addition of graphite . If the total pressure at equilibrium is 0*8 atm , the value of K is

A vesselat 1000 K containsCO_(2) with a pressure of 0.5 atm . Some of

1.	A vesselat 1000 K containsCO_(2) with a pressure of 0.5 atm . Some of the CO_(2) is converted intoCO on the addition of graphite . If the total pressure at equilibrium is 0*8 atm , the value of K is
Answer» <html><body><p>3 atm <br/>`<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>3 `atm<br/>`018 atm`<br/>`1*8 ` atm</p>Solution :`{:(,CO_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)(<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>),+,C(s),hArr,2CO(g)),(" <a href="https://interviewquestions.tuteehub.com/tag/intial-2746226" style="font-weight:bold;" target="_blank" title="Click to know more about INTIAL">INTIAL</a> ",0.5 atm,,,,),("At eqm.",0.5 -p,,,,2 p):}` <br/> `:. (0.5 -p) +2 p = 0.8" atm "or p=0.3 " atm "`<br/> `K=(p^(2) CO)/p_(CO_(2)) = (0.6)^(2)/((0.5 -0.3)) = (0.6 xx0.6)/0.2 = 1.8 " atm", `</body></html>