1.

A vesselat 1000 K containsCO_(2) with a pressure of 0.5 atm . Some of the CO_(2) is converted intoCO on the addition of graphite . If the total pressure at equilibrium is 0*8 atm , the value of K is

Answer»

3 atm
`0*3 `atm
`0*18 atm`
`1*8 ` atm

Solution :`{:(,CO_(2)(G),+,C(s),hArr,2CO(g)),(" INTIAL ",0.5 atm,,,,),("At eqm.",0.5 -p,,,,2 p):}`
`:. (0.5 -p) +2 p = 0.8" atm "or p=0.3 " atm "`
`K=(p^(2) CO)/p_(CO_(2)) = (0.6)^(2)/((0.5 -0.3)) = (0.6 xx0.6)/0.2 = 1.8 " atm", `


Discussion

No Comment Found