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A voltmeter which can measure 2 V isconstructed by using a galvanometer of resistance `12 Omega` and that produces maximum deflection for the current of 2mA. Then the resistance R is A. `888 Omega`B. `988 Omega`C. `898 Omega`D. `999 Omega` |
Answer» Correct Answer - B `R=V/I_(g)-G` Putting `V=2 V, I_(g)= 2 mA= 2 xx 10^(-3) A, G=12 Omega`. `therefore R=2/(2 xx 10^(-3)) -12 = 1000 -12=988 Omega` |
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