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A wall is oftwo layers P and Q eachmade of different material . Boththe layers have same thickness . Thetemperature difference between the wall is 36^(@)C. What is the temperature difference acrossthe layer P ? |
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Answer» <P> Solution :For LAYER P , `A = A_(1), l = l_(1) , K = k_(1)`For layer Q , `A = A_(2) , l = l_(2), K = k_(2)` Given`l_(1)= l_(2),A_(1) = A_(2) , K_(1) = 2K_(2)` Let`theta` be THETEMPERATUREAT the junction two layers and `theta_(1), theta_(2)` are the temperatureat the endfaces of P and Q . Given`theta_(1) = theta_(2) = 36^(@)C` under thermal euqilibrium `(Q)/(t) = (k_(1)a_(1)(theta_(1) = theta))/(l_(1)) = (k_(2)A_(2) (theta - theta_(2)))/(l_(2))` |
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