A water drop of diameter 2 mm is split up into 10^(9) indentical water drops. Calculate the work done in this process. (The surface tension of water is 7.3xx10^(-2)Nm^(-1))

A water drop of diameter 2 mm is split up into 10^(9) indentical water

1.	A water drop of diameter 2 mm is split up into 10^(9) indentical water drops. Calculate the work done in this process. (The surface tension of water is 7.3xx10^(-2)Nm^(-1))
Answer» Solution :Let a water drop of radius R be split up into `10^(9)` identical water drops each of radius r. `R=D/2=(2mm)/2=1mm=1xx10^(-3)m` Number of DROPLETS `N=10^(9)` Surface TENSION `(S)=7.3xx10^(-2)Nm^(-1)` `W=4piR^(2)S[n^(1//3)-1]` `=4pi(10^(-3))^(2)xx7.3xx10^(-2)[(10^(9))^(1//3)-1]` `=9.17xx10^(-5)J`