1.

A water drop of diameter 2mm is split upto into 10^(9) identical water drops. Calculate the work done in this process. (The surface tension of water is 7.3xx10^(-2)Nm^(-1)).

Answer»

Solution :Let a water drop of radius R be split up into `10^(9)` identical water drops each of radius r.
`R=(D)/(2)=(2MM)/(2)=1mm=1xx10^(-3)m`
Number of droplets `n=10^(9)`
Surface tension `(S)=7.3xx10^(-2)Nm^(-1)`
`W=4piR^(2)S[n^(1//3)-1]`
`=4pi(10^(-3))^(2)xx7.3xx10^(-2)[(10^(9))^(1//3)-1]=9.17xx10^(-5)J`


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