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A water fountain on the ground sprinkles water all around it . If the speed of water coming out of the fountain is ` v` , the total area around the fountain that gets wet is :A. `(pi)/(2)(v^(4))/(g^(2))`B. `pi(v^(2))/(g^(2))`C. `pi(v^(2))/(g)`D. `pi(v^(4))/(g^(2))` |
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Answer» Correct Answer - D `A = piR_(max)^(2)` `= pi xx ((U^(2)sin 2 xx 45^(@))/(g))^(2)` `= (piv^(4))/(g^(2))` |
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