1.

A water fountain on the ground sprinkles water all around it . If the speed of water coming out of the fountain is ` v` , the total area around the fountain that gets wet is :A. `pi/2 v^(4)/g^(2)`B. `pi v^(2)/g^(2)`C. `pi v^(2)/g`D. `pi v^(4)/g^(2)`

Answer» Correct Answer - 4
`R_("max")=u^(2)/g`, Area `=pir^(2)=(piu^(2)R_("max")^(2))/g^(2)`


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