A water jet sprinkle water around it. If speed of water is v, then maximum area covered by water jet will b e .......

A water jet sprinkle water around it. If speed of water is v, then max

1.	A water jet sprinkle water around it. If speed of water is v, then maximum area covered by water jet will b e .......
Answer» `(PIV^(2))/(g^(4))` `(piv^(2))/(2g^(2))` `(piv^(4))/(g^(2))` `(piv^(2))/(g)` Solution :MOTIONOF WATER comingout will be projectilemotion Maximumrangeof projectilewill be `R_(max)= (v^(2))/(G ) ` Areacovered= `piR^(2)` `= PI ((v^(2))/(g ))^(2)` `(piv^(2))/( g^(2))`